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0.9x^2=5x^2-3.8
We move all terms to the left:
0.9x^2-(5x^2-3.8)=0
We get rid of parentheses
0.9x^2-5x^2+3.8=0
We add all the numbers together, and all the variables
-4.1x^2+3.8=0
a = -4.1; b = 0; c = +3.8;
Δ = b2-4ac
Δ = 02-4·(-4.1)·3.8
Δ = 62.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{62.32}}{2*-4.1}=\frac{0-\sqrt{62.32}}{-8.2} =-\frac{\sqrt{}}{-8.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{62.32}}{2*-4.1}=\frac{0+\sqrt{62.32}}{-8.2} =\frac{\sqrt{}}{-8.2} $
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